2x^2+140x-1600=0

Solution for 2x^2+140x-1600=0 equation:

2x^2+140x-1600=0

a = 2; b = 140; c = -1600;
Δ = b2-4ac
Δ = 1402-4·2·(-1600)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32400}=180$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-180}{2*2}=\frac{-320}{4}
=-80
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+180}{2*2}=\frac{40}{4}
=10
$